Python math.floor Examples

Initial example. Here we use math.floor on some numbers. Note that the first number 100 is returned unchanged. Floor() does not modify integers.

Detail Floor does not round upon the value 100.9. Instead it always reduces the number to be less.

import math # Some numbers to take floors of. value0 = 100 value1 = 100.1 value2 = 100.5 value3 = 100.9 # Take floor of number. floor0 = math.floor(value0) print(value0, ":", floor0) # Take other floors. print(value1, ":", math.floor(value1)) print(value2, ":", math.floor(value2)) print(value3, ":", math.floor(value3))

100 : 100 100.1 : 100 100.5 : 100 100.9 : 100

NameError. Sometimes when writing Python programs I make this error. There is no "floor" in Python. We must use math.floor to use the floor function.

Error

number = 78.6 # This will not work. result = floor(number)

Traceback (most recent call last): File "C:\programs\file.py", line 5, in <module> result = floor(number) NameError: name 'floor' is not defined

Negative floors. With negative numbers, math.floor has the same logical result as with positive ones. Numbers are always reduced. Negative numbers will become more negative.

import math # Use math.floor on a negative number. result = math.floor(-1.1) print(result) result = math.floor(-1.9) print(result)

-2 -2

Benchmark, floor dictionary. I wanted to test whether a dictionary lookup could be faster than a math.floor call. I found math.floor is fast—much faster than calling get().

Dictionary

Version 1 This version of the code uses math.floor to get the floor of each number.

Version 2 Here we look up a value in a dictionary to get a cached floor value for a number.

Result Using a dictionary to memoize (cache) the result of math.floor is a big slow down. Just use math.floor directly.

import time, math # Floor dictionary. floor_dict = {100.5: 100} print(time.time()) # Version 1: use math.floor. for i in range(0, 100000000): y = 100.5 z = math.floor(y) if z != 100: print(z) break print(time.time()) # Version 2: use dictionary lookup, get method. for i in range(0, 100000000): y = 100.5 z = floor_dict.get(y) if z != 100: print(z) break print(time.time())

1454633830.142 1454633830.727 math.floor = 0.59 s 1454633839.844 floor_dict.get = 9.12 s PyPy3 used

Dot Net Perls is a collection of tested code examples. Pages are continually updated to stay current, with code correctness a top priority.

Sam Allen is passionate about computer languages. In the past, his work has been recommended by Apple and Microsoft and he has studied computers at a selective university in the United States.

This page was last updated on Apr 27, 2023 (edit).

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